Quantity is how many containers you have. The result is how many tributaries fit, the path, and the leftover line rate. The choices stay in the URL, so you can share them.

Result: standard mapping

How many E0s are in an ODU0?

An ODU0 carries 7,560 E0s, per ITU-T G.709, ITU-T G.707 and ITU-T G.704. This path maps STM-4 into ODU0 as a client, then follows that client's tributaries.

7,560

E0s in an ODU0

Working

ODU0 → 1 × STM-4 → 4 × STM-1 → 63 × E1 → 30 × E0

1 × STM-4 in each ODU0 ITU-T G.709Client mappingCBR STM-4 mapped into OPU0.
4 × STM-1 in each STM-4 ITU-T G.7074 × STM-1.
63 × E1 in each STM-1 ITU-T G.70763 VC-12 tributaries: 3 TUG-3 × 7 TUG-2 × 3 TU-12.
30 × E0 in each E1 ITU-T G.70430 voice channels in 32 timeslots. TS0 is framing and TS16 is channel-associated signalling.

1 STM-4
1 × 4 = 4 STM-1s
1 × 4 × 63 = 252 E1s
1 × 4 × 63 × 30 = 7,560 E0s

Leftover capacity

760.320 Mbit/s of each ODU0 line rate (1.244160 Gbit/s) sits outside 7,560 × 64 kbit/s of E0 line rate (483.840 Mbit/s). That remainder is overhead, fixed stuff or justification. It is not another whole tributary.

By bit rate only

Dividing the line rates gives 19,440, which floors to 19,440 E0s by bit rate only. The standard mapping is 7,560. Use the mapping.

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