Quantity is how many containers you have. The result is how many tributaries fit, the path, and the leftover line rate. The choices stay in the URL, so you can share them.
Result: standard mapping
How many E4s are in an OTU2?
An OTU2 carries 64 E4s, per ITU-T G.709 and ITU-T G.707. This path maps STM-64 into ODU2; E4 into STM-1 as a client, then follows that client's tributaries.
64
E4s in an OTU2
Working
OTU2 → 1 × ODU2 → 1 × STM-64 → 64 × STM-1 → 1 × E4
- 1 × ODU2 in each OTU2 ITU-T G.709The OTU2 frame carries exactly one ODU2.
- 1 × STM-64 in each ODU2 ITU-T G.709Client mappingCBR STM-64 mapped into OPU2.
- 64 × STM-1 in each STM-64 ITU-T G.70764 × STM-1.
- 1 × E4 in each STM-1 ITU-T G.707Client mappingAsynchronous E4 mapped into the C-4 / VC-4. This client holds 64 E1s internally; the VC-12 tributary count of an STM-1 is 63.
- 1 ODU2
- 1 × 1 = 1 STM-64
- 1 × 1 × 64 = 64 STM-1s
- 1 × 1 × 64 × 1 = 64 E4s
Leftover capacity
1.796329316 Gbit/s of each OTU2 line rate (10.709225316 Gbit/s) sits outside 64 × 139.264 Mbit/s of E4 line rate (8.912896 Gbit/s). That remainder is overhead, fixed stuff or justification. It is not another whole tributary.
By bit rate only
Dividing the line rates gives 76.89, which floors to 76 E4s by bit rate only. The standard mapping is 64. Use the mapping.
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