Quantity is how many containers you have. The result is how many tributaries fit, the path, and the leftover line rate. The choices stay in the URL, so you can share them.
Result: standard mapping
How many E4s are in an ODU0?
An ODU0 carries 4 E4s, per ITU-T G.709 and ITU-T G.707. This path maps STM-4 into ODU0; E4 into STM-1 as a client, then follows that client's tributaries.
4
E4s in an ODU0
Working
ODU0 → 1 × STM-4 → 4 × STM-1 → 1 × E4
- 1 × STM-4 in each ODU0 ITU-T G.709Client mappingCBR STM-4 mapped into OPU0.
- 4 × STM-1 in each STM-4 ITU-T G.7074 × STM-1.
- 1 × E4 in each STM-1 ITU-T G.707Client mappingAsynchronous E4 mapped into the C-4 / VC-4. This client holds 64 E1s internally; the VC-12 tributary count of an STM-1 is 63.
- 1 STM-4
- 1 × 4 = 4 STM-1s
- 1 × 4 × 1 = 4 E4s
Leftover capacity
687.104 Mbit/s of each ODU0 line rate (1.244160 Gbit/s) sits outside 4 × 139.264 Mbit/s of E4 line rate (557.056 Mbit/s). That remainder is overhead, fixed stuff or justification. It is not another whole tributary.
By bit rate only
Dividing the line rates gives 8.93, which floors to 8 E4s by bit rate only. The standard mapping is 4. Use the mapping.
Share this result. Pairing page